A Fun Game Pt.2

There's a circle with centre O. From O, two lines are drawn to the circumference, at points A and B. From another point, C, on the circumference, a line is drawn passing through O to touch the circumference on the other side at D. Angle AOB is 40 degrees, angle AOC is 65 degrees, and angle BOC is 25 degrees. Another line is extended from A to touch D, and another to touch C. Determine angles BDC and CAD.
You can sketch it out, but I'm going to be like a math teacher and say SHOW YOUR WORKING, you can't just draw it and measure the angles.
You may need to Google circle theorems, I don't know what form you're in so I don't know if you learned those yet.
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There's a circle with centre O. From O, two lines are drawn to the circumference, at points A and B. From another point, C, on the circumference, a line is drawn passing through O to touch the circumference on the other side at D. Angle AOB is 40 degrees, angle AOC is 65 degrees, and angle BOC is 25 degrees. Another line is extended from A to touch D, and another to touch C. Determine angles BDC and CAD.
You can sketch it out, but I'm going to be like a math teacher and say SHOW YOUR WORKING, you can't just draw it and measure the angles.
You may need to Google circle theorems, I don't know what form you're in so I don't know if you learned those yet.

42
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Do this test... start at 1000 add 30 then add 1000 then add 40 add 1000, add 20 add 1000.



now finally add 10 what is your answer?
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Agh, came back to check and realised I typed BDC instead of ADC. ._. Facepalm.
Anyway, ADC should be 32.5, CAD is 90, and BDC would be 12.5.
For ADC and BDC, that's because an angle at the circumference is half as wide as an angle at the centre on the same arc. For CAD, it's because the angle on a diameter is always 90.
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The slope wouldn't be the equation, it would just be a number.
5x-5y=7
5x-7=5y
(5x-7)/5=y (You got up to here)
So... I guess the gradient is 1 (because 5 over 5).
I'm not used to line equations bringing in division.
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